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riadik2000 [5.3K]
3 years ago
6

What is rational number and arithmetic number​

Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

\huge \mathtt \blue{answer}

Here, “p” is a numerator and “q” is a denominator. The examples of rational numbers are 6/5, 10/7, and so on. The rational number is represented using the letter “Q”. Like real numbers, the arithmetic operations, such as addition, subtraction, multiplication, and division are applicable to the rational numbers.

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19 students in the cross is your favorite sport. Explain how to use a circle graph to find the total number of students surveyed
kompoz [17]
Tbh I don’t know the answer
6 0
2 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
Simplify 1/8 - 1/9 x+3/4-2/3x
Afina-wow [57]

Answer:

7/8 - 7x/9

Step-by-step explanation:

;)

8 0
2 years ago
Students receive a 15% discount at the local movie theater. If a student pays the discounted price of $7.65, what is the origina
Over [174]

Answer:

\large \boxed{\$9.00}

Step-by-step explanation:

Let p = the original price of the ticket

\begin{array}{rcl}\text{ Price before discount - discount} & = & \text{sale price}\\p - 0.15p & = & 7.65\\0.85p & = & 7.65\\p & = & \dfrac{7.65 }{0.85}\\\\& = & \mathbf{9.00}\\\end{array}\\\text{The original price of the ticket was $\large \boxed{\mathbf{\$9.00}}$}

Check:

\begin{array}{rcl}9.00 - 0.15(9.00) & = & 7.65\\9.00 - 1.35 & = & 7.65\\7.65 & = & 7.65\\\end{array}

OK.

7 0
2 years ago
Find the solution of this system of equations.
Evgesh-ka [11]

Answer:

Step-by-step explanation:

x + 2y = 8

x - y = 2

x + 2y = 8

-x + y = -2

3y = 6

y = 2

x - 2 = 2

x = 4

(4, 2)

8 0
2 years ago
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