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3 years ago

11

Dissasamble trinom! Number 3

1 answer:

valentina_108 [34]3 years ago

6 0

Look at the picture......

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Consider the system of equations.

frosja888 [35]

Answer:

First part: -10x-4y=-12

Second half: infinitely many solutions

Step-by-step explanation:

Just did the assignment and got it correct

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!!

Contact [7]

The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)

find slope

slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5

pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2

y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D

5 0

3 years ago

You went shopping and bought a bunch of snacks. You brought 3 bags of cheetos, 2 boxes of fruity pebbles, 4 bags of chocolate an

Elenna [48]

Answer:

4/10

Step-by-step explanation:

There are 10 items and 4 chocolates, therefore it is 4/10

5 0

3 years ago

One month, Jon worked 3 hours less than Chaya, and Angelica worked 4 hours more than Chaya. Together they worked 196 hours. Find

OleMash [197]

джон работал на 1 час меньше

3 0

3 years ago

Read 2 more answers

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago