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Mama L [17]
3 years ago
11

Dissasamble trinom! Number 3

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0
Look at the picture......

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Complete the following division problems: 683 ÷ 4 , 212 ÷ 9
vova2212 [387]

683 ÷ 4= 170.75

212 ÷ 9= 23.5555556

1.21=121100

2

-                   = 2.0E-5


100000

8 0
3 years ago
Write an equation of the line passing through the points (4.15) and (-1. - 15).
jolli1 [7]

Answer:

y = 6x - 9

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, 15)

Point (-1, -15)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-15-15}{-1-4}
  2. Subtract:                       m=\frac{-30}{-5}
  3. Divide:                          m=6

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 6x + b
  2. Substitute:              -15 = 6(-1) + b
  3. Multiply:                  -15 = -6 + b
  4. Isolate <em>b</em>:                 -9 = b
  5. Rewrite:                   b = -9

<u>Step 4: Write linear equation</u>

<em>Substitute in all variables.</em>

y = 6x - 9

And we have our answer!

4 0
3 years ago
14. If m is a positive integer, then which of the
Dmitriy789 [7]

Hello!

Simplifying :

⇒ 4m + 4m + 4m + 4m

⇒ 4(4m)

7 0
2 years ago
Read 2 more answers
3x=3x+4 is it no solution
Katena32 [7]
Correct!

no matter what value we enter in for x, the statement will always be incorrect

3(1)=3(1)+4
3 = 3+4
3\neq7
8 0
3 years ago
Find the domain over which the function y = x + 6x is monotonic increasing.
iragen [17]

Answer:

x > -3

\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing:  always increasing.  
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation:  \sf y=ax^2+bx+c

\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}

Given function:

\sf y=x^2+6x

Therefore, x-value of function's vertex:

\sf \implies x= -\dfrac{6}{2}=-3

<u>Final Solution</u>

The function is increasing when x > -3

\sf (-3, \infty)

4 0
3 years ago
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