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VARVARA [1.3K]
3 years ago
8

Two number cubes each have sides that are labeled 1 to 6. Isis rolls the 2 number cubes. What is the probability that the sum of

the numbers will equal 4?
Mathematics
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

1/12 or 0.0833...

Step-by-step explanation:

There are 36 different possible outcomes for rolling the number cubes. To get a sum of 4 you would need to roll a 1 and 3 (2 possibilities, each cube could roll a 1 or a 3) or a 2 and a 2 (1 possibility, each has to roll the same number). Since there is no 0 or negative numbers, these are your only possibilities. 3 out of 36 possibilities is also equivalent to a 1/12 chance.

Hope this helps

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erma4kov [3.2K]

The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

y = ax^2 + bx + c

The given quadratic equation is 24x^2 + 2x = 15

Let's rearrange the equation

24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0

This implies that

  • a = 24
  • b = 2
  • c = -15

The equation or formula of quadratic formula is given as

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}

We can substitute the values into the equation and solve

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

From the calculations above, the solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

Learn more on quadratic equation here;

brainly.com/question/8649555

#SPJ1

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1 year ago
Help please I need the answer
Mazyrski [523]

Answer:

Albany

Step-by-step explanation:

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