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4 years ago

Which relation Is a function? From the graphs

Mathematics

2 answers:

monitta4 years ago

8 0

Answer:

Bottom right

Step-by-step explanation:

For a set of numbers to be function the independent variable must have only one value in the dependent variable.

You can do it with graphs or tables.

Here you can analyze each graph.

Top Left:

for x = -1, y = -1 and also y = 3, then it isnt a function because there are 2 values in y for 1 value in x

Top Right:

for x = 0, y = -1 and also y = 2, it isnt a function

Bottom Left:

for x = -2, y= -2 and also = 1, for x = 2, y = -2 and also y = 0, it isnt a function

Bottom right:

Each x has only 1 y. It is a function

kicyunya [14]4 years ago

5 0

Answer:

3rd one

Step-by-step explanation:

because it's close

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Given quadrilateral RSTU, determine if each pair of sides (if any) are parallel and which are perpendicular for the coordinates

WINSTONCH [101]

Check the picture below.

so, clearly UR is not parallel to ST, but is likely that UT is parallel to RS.

keeping in mind that parallel lines, have the same exact slope, let's check the slope for UT as well as RS, if they are the same, then indeed both are parallel,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&R&(~ 1 &,& -3~) 
% (c,d)
&S&(~ 4 &,& -1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-3)}{4-1}\implies \cfrac{-1+3}{4-1}\implies \cfrac{2}{3}\\\\
-------------------------------$

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&U&(~ -4 &,& -2~) 
% (c,d)
&T&(~ 2 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{2-(-4)}\implies \cfrac{2+2}{2+4}\implies \cfrac{4}{6}\implies \cfrac{2}{3}$

there you have it, notice the slopes of each.

from the picture, clearly there are no right-angles at vertices U and R, however at S and T, it looks like, but we dunno.

well, we know UT || RS, now if ST ⟂ RS, then ST will have a negative reciprocal slope to RS, namely whatever the slope of RS is, ST will be the negative reciprocal of that, so let's check what is the slope of ST then,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{2}{3}\\\\
negative\implies -\cfrac{2}{ 3}\qquad reciprocal\implies \boxed{- \cfrac{ 3}{2}}\\\\
-------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 4 &,& -1~) 
% (c,d)
&T&(~ 2 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-1)}{2-4}\implies \cfrac{2+1}{2-4}\implies \boxed{-\cfrac{3}{2}}$

and if ST ⟂ RS, then ST ⟂ UT.

8 0

3 years ago

I need help with pythagoras’ theorem

fomenos

Answer:

Pythagoras’ theorem is a way to find a side or hypothesis when you have 2 sides.

The formula is: a^2 + b^2 = c^2

a and b are sides

c is the hypothesis

Ex: A triangle has a leg that is 5 inches and a leg that is 7 inches. Find the hypothesis using Pythagoras' theorem.

A leg is another way of saying a side.

5^2 + 7^2 = c^2

25 + 49 = x^2

sqrt(74) = sqrt(x^2)

sqrt(74) inches = hypothesis

Ex: A triangle has a leg that is 9 feet and a hypothesis that is 25 feet. Find the other leg using Pythagoras' theorem.

9^2 + b^2 = 25^2

81 + b^2 - 81 = 625 - 81

sqrt(b^2) = sqrt(544)

b = sqrt(554)

Do you understand more?

4 0

3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!

Yakvenalex [24]

I got a dilation of 33%

6 0

3 years ago

Read 2 more answers

Help with this math question.

algol [13]

Answer:

FH & FG

Step-by-step explanation:

A triangle is formed by a base (the bottom) and two legs (sides).

4 0

3 years ago

The owner of a automobile repair center purchased new electronic diagnostic equipment for $12000. He paid 10 precent down and th

jek_recluse [69]

The owner of a automobile repair center purchased new electronic diagnostic equipment for $12000. He paid 10 pERcent down and then paid 60 pAYMENTS monthly of $203.81.

Net loan, P=12000*0.9=10800
Monthly payment, A=203.81
Number of payments, n=60

Let i=APR

A=P(i/12*(1+i/12)^n)/((1+i/12)^n-1)
Substituting values
203.81=10800(i/12*(1+i/12)^60)/((1+i/12)^n-1)

=>
12*203.81/10800=i(1+i/12)^60/((1+i/12)^60-1)

To solve for i, we form the iterative equation:
(1+i/12)^60=(12*203.81/10800)/i*((1+i/12)^60-1)
i=12*(12*203.81/10800*((1+i/12)^60-1)/i)^(1/60-1)
try i=0.05,
f(0.05)=0.05
Therefore the APR is 5%

8 0

3 years ago

Which relation Is a function? From the graphs ​

Which relation Is a function? From the graphs