Answer:

length = 6

width = 6

height = 6

Step-by-step explanation:

Area of the square = 6 * 6

Area of the square = 36

The perimeter = 6 + 6

The perimeter = 12

so 36 is 3 times bigger than 12

7 0

1 year ago

Evaluate. 7^3 <br> A) 21<br> B) 49<br> C) 81<br> D) 343

Mademuasel [1]

The answer is a 73/3=21

5 0

2 years ago

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Find the sum of the equation

stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

5 0

1 year ago

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