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Rasek [7]
3 years ago
7

Apple weights in an orchard are normally distributed. from a sample farmer fred determines the mean weight of a box of apples to

be 270 oz. with a standard deviation of 10 oz. he wonders what percent of the apple boxes he has grouped for sale will have a weight less than 255 oz. carl calculates the z-score corresponding to the weight 255 oz. = - using the table (column .00), carl sees the area associated with this z-score is 0. carl rounds this value to the nearest hundredth or 0. now, carl decides to find the percent associated with boxes less than 255 oz. so he rounds to hundredths and subtracts 0.50 - 0. = %.
Mathematics
2 answers:
Serjik [45]3 years ago
7 0
<span>Mean = 270 Standard deviation = 10 x = 255 Formula for z-score, z = (x - mean)/SD z = (255 - 270) / 10 => z = -15 / 10 => z = -1.5 So by referring to z-table, -1.5 correlates to 0.0668 that implies to 0.07 So 7% of the boxes of Apples weight less than 255oz. The percentage of boxes is in the range of 255 oz and 270 oz, Now calculating the requiring percentage 50% - 7% = 43%</span>
aalyn [17]3 years ago
3 0

Answer:

2.07 is the answer as of e.2020

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

x^2 + 7x + 10 = 0

Subtract 10 from both sides.

x^2 + 7x = -10

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = \dfrac{9}{4}

Now we use the square root property, if

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x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}

x + \dfrac{7}{2} = \pm \dfrac{3}{2}

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3 years ago
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aleksklad [387]

Answer:

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Step-by-step explanation:

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8 0
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Can so one explain please? So confused.
Fiesta28 [93]

Answer:

Step-by-step explanation:

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Answer:

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