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sashaice [31]
3 years ago
15

In a right triangle, the length of one leg is 6 units. The length of the other leg is 8 units. What is the length of the hypoten

use (hint: use Pythagorean Theorem)?
Mathematics
2 answers:
lozanna [386]3 years ago
7 0
hypotenuse =  \sqrt{6^2+8^2}= \sqrt{36+64}= \sqrt{100}=10 \ units
Lesechka [4]3 years ago
6 0
Applying the Pythagorean Theorem, a^2 + b^2 = c^2, we can insert the numbers 6^2 + 8^2 = c^2, or 36 + 64 = √100, or 10. So the hypotenuse is 10 units.
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Write the fraction as a decimal. Round your answer to the nearest hundredth 86/96
gregori [183]

Answer:

0.90

Step-by-step explanation:

Hope this Helps!!

3 0
2 years ago
The cylindrical water tank on a semitrailer has a length of 20 feet. The volume of the tank is equal to the product of pi, the s
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Answer:

V = 20πr²

Step-by-step explanation:

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7 0
3 years ago
A factory makes
Digiron [165]

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3 0
2 years ago
Find the slope of the line graph above
MakcuM [25]

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6 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
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