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2 years ago

Can some help me with this! Will Mark brainliest ❤️

Mathematics

1 answer:

Serhud [2]2 years ago

3 0

If TU is 7.5 and UC is 17.5, TV = 25 because you just add the two together

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Please help Meeeeeeeeeee

sweet [91]

Answer:

9 ≤ p

Step-by-step explanation:

-18 ≤ -3p

-18/-3 ≤ p

9 ≤ p

6 0

1 year ago

Read 2 more answers

When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance

bekas [8.4K]

a) $v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

The average speed is equal to the ratio between the total distance ( $d_{tot}$ and the total time taken ( $t_{tot}$ ):

$v=\frac{d_{tot}}{t_{tot}}$

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

$d_1 = (3 h)(60 mph)=180 mi$

So the total distance is

$d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi$

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

$t_{tot}=3 h +t_2$

So, the equation can be rewritten as:

$v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

b) 0.50 h (half a hour)

Since we know the value of the average speed, $v=57.14 mph$ , we can substitute it into the previous equation to find the value of $t_2$ , the time the trucker drove in the city:

$v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h$

3 0

3 years ago

Round 6.09933418366 to 4 decimal places

telo118 [61]

Answer:

6.113 i believe to be so

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2 years ago

Common numbers for 15 18 and 12

Aleks [24]

<span>Common numbers for 15 18 and 12: 1 and 3</span>

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2 years ago

In the figure, m and n are rays.

suter [353]

Is there a picture to go along with this??

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3 years ago