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Vilka [71]
3 years ago
7

Can some help me with this! Will Mark brainliest ❤️

Mathematics
1 answer:
Serhud [2]3 years ago
3 0
If TU is 7.5 and UC is 17.5, TV = 25 because you just add the two together

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Pls help and no unnecessary typin* I will report
satela [25.4K]

\large\bf{\underline{Given :}}

  • An isosceles triangle ABC
  • AD is a bisector of ∠‎A

__________________________________________

\large\bf{\underline{To \:prove :}}

  • BD = DC

__________________________________________

\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}

{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}

{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}

{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}

\large\bf{\underline{Hence}}

  • By ASA criteria ∆ABD congurant to ∆ADC

__________________________________________

\large\bf{\underline{So}}

  • By CPCT ( corresponding parts of congurant triangle )

\large\bf{BD = DC}

__________________________________________

\large\bf{\underline{Note :}}Slide to view full answer.

6 0
3 years ago
A ten pound bag of cherries cost $33.50. How much is one pound of cherries?
Rashid [163]
Each pound costs $3.35. Hope this helped
3 0
3 years ago
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Which is the location of the dairy?
mixer [17]

Answer:

the uter of a cow.......

6 0
3 years ago
A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
1. What number is 35% of 80?<br>​
Stella [2.4K]

Answer: 28

Step-by-step explanation: 80 x 0.35 = 28

6 0
2 years ago
Read 2 more answers
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