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3 years ago

If point C is between points A and B, then ________ + CB=AB

Mathematics

1 answer:

Strike441 [17]3 years ago

8 0

AC+CB=AB
Where AC=CB
This is because C divides AB into two equal parts

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I don’t understand this and it’s due tomorrow. Pls help

olya-2409 [2.1K]

Answer: H

Step-by-step explanation:

So this is called a problem you would use PEMDAS or (please-excuse-my-dear-aunt-sally)

Parenthesis

Exponents

Multiply

Divide

Addition

Subtract

In this sens, since parenthesis are present you do them first so it would be H

3 0

3 years ago

Which best describes the association between variables x and y?

dybincka [34]

The answer is Strong Positive

3 0

3 years ago

Given: 3x+7+2(4x+1) = 3(x-1) -4 prove: x=-2

denis23 [38]

Answer:

x = -2, proven below.

Step-by-step explanation:

3x + 7 + 2(4x+1) = 3(x-1) - 4

3x + 7 + 8x + 2 = 3x - 3 - 4

9 + 11x = 3x - 7

16 + 11x = 3x

16 = - 8x

-2 = x

7 0

4 years ago

Angle c is inscribed in circle O. AB is a diameter of circle O. what is the radius of circle.

Llana [10]

Answer:

The value of radius is 7.5 units

Step-by-step explanation:

Given that a line that pass through the origin and form a triangle is a right-angle triangle. So in order to find the diameter/hypotenuse, you have to use Pythogaras Theorem :

${c}^{2} = {a}^{2} + {b}^{2}$

Let a = 12 units,

Let b = 9 units,

Let c = hypo.,

${hypo.}^{2} = {12}^{2} + {9}^{2}$

${hypo.}^{2} = 225$

$hypo. = \sqrt{225}$

$hypo. = 15 \: \: units$

We have found out that the hypotenuse of the triangle is the diameter of circle. So in order to find radius, you have to divide it by 2 :

$radius = diameter \div 2$

$radius = 15 \div 2$

$radius = 7.5 \: \: units$

6 0

4 years ago

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

3 years ago