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kolbaska11 [484]

3 years ago

8

ABC has coordinates of A (-8,-8), B (4,-2), and C (2,2). Find the coordinates of its image after a dilation centered at the orig

in with a scale factor of 1.5

1 answer:

julsineya [31]3 years ago

7 0

A (-9.5, -9.5) B (5.5,-2.5) C (3.5,3.5)

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0

3 years ago

Find the first three terms of the sequence below. Tn=n2+2n+9

klasskru [66]

$\\ \bull\tt\longrightarrow T_n=n^2+2n+9$

$\\ \bull\tt\longrightarrow T_1=1^2+2(1)+9=1+2+9=12$

$\\ \bull\tt\longrightarrow T_2=2^2+2(2)+9=4+4+9=17$

$\\ \bull\tt\longrightarrow T_3=3^2+2(3)+9=9+6+9=24$

8 0

3 years ago

7. Solve |3x – 2| = |x + 1|

Vladimir [108]

2x -2 =1

2x = 3

x =1.5

5 0

3 years ago

Please can someone answer this.

ivanzaharov [21]

Answer:

• x = -4, x = 0, x = 1

Step-by-step explanation:

x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)

The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)

Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.

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Of course, your graphing calculator can answer this almost as quickly.

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3 years ago

Which number completes the square?<br> 2x^2 - 12x +

Fofino [41]

67-x-20 hope this helped!!

7 0

2 years ago