Can someone please help me with these questions? Thanks

Vlad [161]

Answer:
y = -1 + -0.75x
explanation:

7 0

3 years ago

A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0

3 years ago

Toko follows a budget to buy supplies to paint his room. He spends 1/2 of his budget on a roller, a tray, and tape. He spends $1

Natasha_Volkova [10]

The answer is $36.

B - budget
So the calculation is as following:
$B= \frac{1}{2}B + 12.27 + \frac{3.82}{ \frac{2}{3} } = \frac{1}{2}B + 12.27 + \frac{3.82*3}{2}= \frac{1}{2}B + 12.27 +5.73$
$B= \frac{1}{2} B + 18$
$B- \frac{1}{2}B = 18$
$\frac{1}{2}B = 18$
$B = 18*2=36$

3 0

3 years ago

In another survey, Jane found that 25% of the total number of teenagers surveyed like sandwiches. If 50 teenagers like sandwiche

34kurt

Set up a proportion: 25/100 = 50/n where n = # of teens surveyed
Simplify fraction: 1/4 = 50/n
Cross multiply: n = 200
So 200 teens were surveyed.

7 0

3 years ago

Match the story to the equation: If 1/3 of the drive to Han's school is 2 miles, how long is the whole drive to school? Group of

lubasha [3.4K]

Answer:

2x1/3 sorry if not right

Step-by-step explanation:

5 0

3 years ago