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Harman [31]
3 years ago
12

What decimal is represented by this expanded form? 2 x 10,000 7 x 1,000 4 x 100 9 x 1 3 x 1/10 8 x 1/1,000?

Mathematics
1 answer:
Maslowich3 years ago
8 0
27,409.308 <========
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38 divided by 817,152​
Olenka [21]

Your answer is 0.00004650297619

8 0
2 years ago
Calculate the volume of the figure.
dimaraw [331]

Answer: The volume is 33 cubic centimeters.

Step-by-step explanation:

First find the volume of the square pyramid on top of the cube. To find the volume of the square pyramid you use the volume  a^2*h/3 a is the side length of the base of the square pyramid and h is the height all divide by 3.

So we can say that the side length of the base of the square pyramid is 3 because it has the same side length base as the cube.

V= 3^2 * 2 /3

V= 9 * 2 /3

V= 18/3

v= 6  

So the volume of the square pyramid is 6 so now we need to find the volume of the cube and add them together.

Volume of the a cube uses the formula s^3 where s is the side length.

V= 3^3

v= 3*3*3

v= 27  

The volume of the cube is 27.

Add 6 and 27 to find the total volume.

6 +27 = 33

8 0
3 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
3 years ago
Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to point distance. the calculation is: d
Ronch [10]

we are given two points as

(1.0, 2.0) and (1.0, 5.0)

so,

(x1, y1)= (1.0 , 2.0)

(x2, y2)= (1.0 , 5.0)

x1=1 , y1=2

x2=1 , y2=5

now, we can use distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

now, we can plug values

and we get

d=\sqrt{(1-1)^2+(5-2)^2}

d=\sqrt{(0)^2+(3)^2}

d=\sqrt{(3)^2}

d=3

so, distance between points is 3...........Answer

5 0
3 years ago
If r(x) = 2x^2 – 5x + 1, find r(x + 2)
quester [9]

Step-by-step explanation:

1 Expand by distributing terms.

rx+r×2

2 Regroup terms.

rx+2r

3 0
3 years ago
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