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Otrada [13]
3 years ago
6

What is the solution to the inequality? −4x − 8 > −20

Mathematics
2 answers:
andre [41]3 years ago
7 0
X < -3 is what the answer is
lara [203]3 years ago
3 0
X < -3 is the answer it is eazy just add 8 to both sides=12 and then divide both sides by 4 to get -3
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If the diameter of a circle with a circumference of 12.6 mm is divided by 2, what is the circumference of the new circle?
Archy [21]
12.6/2=6.3 is the answer hope it is helpful
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28 points !! please help
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Sam's closet contains blue and green shirts. He has eight blue shirts, and seven green shirts. Five of the blue shirts have stri
Bas_tet [7]

Answer:  The answer is 80%.


Step-by-step explanation:  Let us define the following events.

B = the event that the shirt is blue,

G = the event that the shirt is green

and

S = the event that the shirt is striped.

So, n(B) = 8,  n(G) = 7,  n(B and S) = 5, n(G and S) = 4.

n(S) = 5 + 4 = 9.

We have

n(B\cup S)=n(B)+n(S)-n(B\cap S)=8+9-5=12.

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3 0
3 years ago
A. A container holds 0.500 qt of liquid. How many milliliters of lemonade will it hold?
Nady [450]

Answer:

<em>A container can hold 473.176 ml</em>

<em>42.52 grams is nitrogen. </em>

Step-by-step explanation:

<u>Part A:</u>

We have given that a container holds 0.500 qt . Now we have to find how many milliliters of lemonade it can hold.

We know that 1 qt = 946.353 ml

To find how many milliliters of lemonade a container hold, we have to convert 0.500qt into ml.

As we have mentioned above that 1 qt = 946.353 ml

Multiply the volume value by 946.353 .

0.500 * 946.353

= 473.176 ml

<em>It means a container can hold 473.176 ml</em>

<u>Part B:</u>

Convert the unit oz  to grams. The ratio is 1 ounce is to 28.34 grams.

We have 10.0 oz.

10* 28.34 = 283.495

This would mean 10 oz is equivalent to 283.50 grams. It is given that the fertilizer is 15% by mass nitrogen. It means for every 100 g of fertilizer 15 grams of that is nitrogen. Hence for every 283.50 grams of fertilizer

<em>283.50 * (15/100) = 42.52 grams is nitrogen. </em>

<em></em>

8 0
3 years ago
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