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Morgarella [4.7K]
3 years ago
9

Every polynomial function of degree 3 with real coefficients has exactly three real zeros. choose the correct answer below. fals

e true
Mathematics
2 answers:
Vikki [24]3 years ago
8 0
False.  It can also have complex number  zeroes.
EleoNora [17]3 years ago
7 0

Answer:

False

They can also have one real zero and two complex zeroes.

Step-by-step explanation:

It is false. They can also have complex zeros.

For example.

(x-3)*(x^{2} + 4x + 5)

Has one real zero(3), and two complex zeros.

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Answer:

will this help?

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What does 100000000009099998878352trillon plus 22 equal
kap26 [50]

Answer:

100,000,000,009,099,998,878,374

Step-by-step explanation:

8 0
2 years ago
40 points!!! please tell me how to do it not what the answer is :D
Julli [10]

Answer:

C

Step-by-step explanation:

You first distribute within the parentheses which is -(-z-2). This is going to make everything positive as everything in the parentheses is negative. You should get z+2. Next, you plug that back in. It should be-3z+z+2. You simplify to get -2z+2. Hope this helps!

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2 years ago
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Find the values of x and y.<br> help please work has to be shown ..
Likurg_2 [28]

Answer:

x = 7 and y = 17

Step-by-step explanation:

16x + 9x + 5 = 180 cuz they are supplementary

25x = 175

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5 0
2 years ago
Simplify. final answer should be written in standard form (a+b)(3a-b)(2a+7b)
algol13

we have

(a+b)(3a-b)(2a+7b)

step 1

Solve

apply distributive property

(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2

step 2

Multiply (3a^2-4ab-b^2) by (2a+7b)

6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3

answer is

<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
6 0
1 year ago
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