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strojnjashka [21]
3 years ago
10

Whats - 1/64 as cubed

Mathematics
2 answers:
AnnyKZ [126]3 years ago
3 0

Answer:

cubed also means the square root which is 8.

explained:

The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as 3√64=4. The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as 3√−64=−4. The cube root of 8 is written as 3√8=2.

kondor19780726 [428]3 years ago
3 0

Answer: 1/4

Step-by-step explanation:

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marta [7]

Step-by-step explanation:

(-)(-) = +

-  \frac{3}{5}  +  \frac{5}{9}

-   \frac{27}{45}  +  \frac{25}{45}

- \frac{2}{45}

8 0
3 years ago
Help with my math please!!!
madam [21]

Answer:

x-12≤7

x≤19

Step-by-step explanation:

less than means it comes after

x-12

is at most means less than or equal to

x-12≤7

Add 12 to each side

x-12+12≤7+12

x≤19

7 0
3 years ago
Read 2 more answers
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

6 0
3 years ago
URGENT!! please help me )):​
Dimas [21]
[-5] [7] [6] [10]

U is union thus list everything in A and B
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3 years ago
Question 3
german

Part A :

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Part B :

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