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ahrayia [7]
2 years ago
8

When taking a 17 question multiple choice test, where each question has 3 possible answers, it would be unusual to get or more q

uestions correct by guessing alone?
Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer: If you’re talking on a percentage basis, it would be extremely unlikely to get a majority of the questions correct.

Step-by-step explanation:

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Please help me with this problem please
11111nata11111 [884]

9514 1404 393

Answer:

  • shortest: 11 1/8 in
  • longest: 11 3/8 in

Step-by-step explanation:

It should be no surprise that the shortest allowable length is the nominal length less the full allowed tolerance:

  11 1/4 - 1/8 = 11 1/8 . . . inches

__

Likewise, the longest allowable length is the nominal length plus the maximum tolerance:

  11 1/4 + 1/8 = 11 3/8 . . . inches

_____

Of course, you know that 1/4 = 2/8, so adding or subtracting 1/8 gives the fractions shown above.

5 0
3 years ago
Can someone please help me
nadya68 [22]

Answer:

<u>Right</u><u> </u><u>option</u><u> </u><u>is</u><u> </u><u>B</u><u>.</u><u> </u>

Step-by-step explanation:

\sf  \longrightarrow \frac{ \sec x \sin( - x)  +  \tan( - x) }{1 +  \sec( - x) }  \\  \\  \sf \longrightarrow  \frac{ \sec x( -  \sin x) -  \tan x}{1 +  \sec x}  \\  \\  \sf  \longrightarrow   \frac{  - \frac{1}{ \cos x } \times  \sin x -  \tan x }{1 +  \sec x}  \\  \\  \sf  \longrightarrow \frac{ -  \tan x -  \tan x}{1 +  \sec x}   \\  \\  \sf  \longrightarrow  \frac{ - 2 \tan x}{1 +  \sec x}  \\  \\  \sf \longrightarrow   \frac{  \frac{ - 2 \sin x}{ \cos x} }{1 +  \frac{1}{ \cos x} }  \\  \\  \sf  \longrightarrow  \frac{  \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} }  \\  \\     \boxed{  \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1}  }}

4 0
1 year ago
A storage container shaped as a rectangular prism can hold 896 wooden cube blocks with edge lengths of 14 ft.
Savatey [412]

Answer:

224

Step-by-step explanation:

Hope this helps!!

3 0
2 years ago
The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
Two lawn care companies are competing for a landscaping contract. Company A charges a $5 daily consulting fee plus $8 per square
gladu [14]
5 + 8s = 15 + 3s
8s - 3s = 15 - 5
5s = 10
s = 10/5
s = 2 <=== they will charge the same at 2 sq ft
8 0
3 years ago
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