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eduard
3 years ago
14

the first term of a geometric progression is 12 and the second term is -6. Find the (i) the tenth term of the progression (ii) t

he sum to infinity
Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Step-by-step explanation:

a1=ar⁰=12 A2=ar¹=-6

a=12 ar=-6

12r=-6

r=-6/12

r=-1/2

a10=ar⁹

=12*(-1/2)⁹

=12*(-512)

=-3/128

S∞ = a1 / (1-r )

=12/(1-1/2)

=12*1/2

=6

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Rewrite the function in standard form.<br> f(x)= 3(x + 5)2 - 7
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3 0
3 years ago
Solve for x,y, and z
Lostsunrise [7]
Equation 1)  3x + 2y - 5z = 3
Equation 2)  4x - 2y - 3z = -10
Equation 3)  5x - 2y - 2z = -11

Add equation 1 with equation 2.

Equation 4)  7x - 8z = 7

Then subtract equation 3 from equation 2.

Equation 5)  -x -z = 1

Multiply all of equation 5 with 7.

5)  -7x - 7z = 7
4)  7x - 8z = 7

Add equations together.

z = 14

Plug in 14 for z in equation 4.

7x - 8z = 7

7x - 8(14) = 7

7x - 112 = 7

7x = 119

x = 17

Plug in 17 for x in equation 1, and 14 for z.

1)  3x + 2y - 5z = 3

3(17) + 2y - 5(14) = 3

51 + 2y - 70 = 3

2y - 19 = 3

2y = 22

y = 11

So, x = 17, y = 11, and z = 14

~Hope I helped!~



3 0
3 years ago
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