the first term of a geometric progression is 12 and the second term is -6. Find the (i) the tenth term of the progression (ii) t
he sum to infinity
1 answer:
Step-by-step explanation:
a1=ar⁰=12 A2=ar¹=-6
a=12 ar=-6
12r=-6
r=-6/12
r=-1/2
a10=ar⁹
=12*(-1/2)⁹
=12*(-512)
=-3/128
S∞ = a1 / (1-r )
=12/(1-1/2)
=12*1/2
=6
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