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eduard
3 years ago
14

the first term of a geometric progression is 12 and the second term is -6. Find the (i) the tenth term of the progression (ii) t

he sum to infinity
Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Step-by-step explanation:

a1=ar⁰=12 A2=ar¹=-6

a=12 ar=-6

12r=-6

r=-6/12

r=-1/2

a10=ar⁹

=12*(-1/2)⁹

=12*(-512)

=-3/128

S∞ = a1 / (1-r )

=12/(1-1/2)

=12*1/2

=6

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Which expression is equivalent to 4(x^3)(2x)^-4
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Answer:

=\frac{4x^{3}}{16 x^{4}}

Step-by-step explanation:

4(x^{3} )(2x)^{-4}

=\frac{4x^{3}}{(2x)^{4}}

=\frac{4x^{3}}{2^{4} x^{4}}

=\frac{4x^{3}}{16 x^{4}}

3 0
3 years ago
Answer answer it it .
charle [14.2K]

Answer:

d 3

Step-by-step explanation:

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3 years ago
Solve please<br> A. 1/6m-3=-5<br> B. 2/3x-3=1/2x-7<br> C. x+x/2-4=x/4
AysviL [449]

Answer:

A m = 48

B x = -24

C x = 16

Step-by-step explanation:

A. 1/6m - 3 = 5

1/6m = 5+3

1/6m = 8

multiply both side by 6

m = 8×6

m = 48

B. 2/3x-3 = 1/2 x-7

2/3 x - 1/2 x = -7 +3

1/6 x = -4

multiply 6 to the both side

x = -4×6

x= -24

C.x+x/2-4= x/4

x+x/2 - x/4 = 4

x + l/2 x - 1/4 x = 4

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multiply both side by 4

x= 4×4

x = 16

4 0
2 years ago
.84 is 1/10 as much as
maw [93]
Hello there.
<span>
84 is 1/10 as much as  
</span>
0.84

4 0
3 years ago
How many real solutions does a quadratic equation have if its discriminant is negative?
kvasek [131]

Answer:

A

Step-by-step explanation:

Discriminant is given by

D = b^{2} -4ac

If it is negative then in quadratic formula the square root part becomes negative which makes the solution complex.

so there cannot be any real solution if the Discriminant is negative or less than 0 ,

The correct option for the given question is

A

3 0
3 years ago
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