Answer:
. The total cost to rent a truck is $100 and $0.20 per km. a. Determine an algebraic model for the relationship between total cost and distance driven. Use Cto represent total cost ($) to rent the truck and d to represent distance driven (km). C=$100+$0.20d b. Create a graphical model. You may use the Linear Graphing Tool or Desmos to create your graphical model. Take a screenshot of your graph and paste it here.
Thank you
3/4 divides by 1/7 =
copy dot flip
3/4 * 7/1
21/4
4 goes into 21 5 times with 1 left over
5 1/4
First, find the total price she would have had to pay (without tax):
2.75+ 3(2.5)+ 1.75=12
If she has half-price multiply the total price by 0.5:
12(.5)=6
Her total price without tax is $6.
The answer is B) $6.00
Hope I helped...
Answer:
A .cos(x)<1
Step-by-step explanation:
According to the first inequality
cos(x)<1
x < arccos 1
x<0
This therefore does not have a solution within the range 0 ≤ x ≤ 2pi
x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.
For the second option
.cos(x/2)<1
x/2< arccos1
x/2<0
x<0
This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.
For the inequality csc(x)<1
1/sin(x) < 1
1< sin(x)
sinx>1
x>arcsin1
x>90°
x>π/2
This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values
For the inequality csc(x/2)<1
1/sin(x/2) < 1
1< sin(x/2)
sin(x/2)> 1
x/2 > arcsin1
X/2 > 90°
x>180°
x>π
This value of x also has a solution within the range.
Therefore option A is the only inequality that does not have a solution with the range.
B, D, and E
The absolute value of -37 is 37.
The absolute value of 37 is also 37.
When you distribute the negative in the parenthesis the -37 becomes positive.
