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valentina_108 [34]
3 years ago
14

one customer purchases 8 bags of cat food. the total weight of ut is 44 pounds. another customer purchases 5 bags of cat food an

d 2 bags of dog food. the total weight of the purchase is 35 pounds​
Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

I would say the dog food is 5.5 pounds and the cat food is 3.75 pounds

LuckyWell [14K]3 years ago
4 0

Answer:

<h2>Each bag of dog foos weighs 2.5 pounds.</h2>

Step-by-step explanation:

The question must be

<em>What's the total weight of a bag of dog food?</em>

<em />

So, we know that the first purchase was 8 bags of cat food and weighed 44 pounds.

Then, the second purchase was 5 bags of cat food and 2 bags of dog food, which weighed 35 pounds.

We can use the first purchase to find the weight of one bag of cat food

c=\frac{44}{8}= 5.5 lb

So, the second expression can be written as

5c + 3d =35

Where c represents cat's food and d represents dog's food

Replacing c=5.5 we have

5(5.5) + 3d =35\\3d=35-27.5\\d=\frac{7.5}{3}\\ d=2.5

Therefore, each bag of dog foos weighs 2.5 pounds.

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Greeley [361]

Answer:

6) -

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Step-by-step explanation:

8 0
3 years ago
The angled lines used to indicate the surfaces which are cut by the imaginary cutting-plane are called:
Scilla [17]

Answer:

Section lines

Step-by-step explanation:

Sectioning is the process of cutting a surface by an imaginary plane, the view of the surface that is cut is shown in the section view.

Section lines are used to indicate where an imaginary cutting plane cuts a material. The imaginary cut is then represented using section lines which are usually thin, crosshatched.

Section lines shows the surface that have been cut by the cutting plane. There are different ways of sectioning such as full section, half section, off set section and so on

8 0
2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
I don’t know how to solve this
V125BC [204]

Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation

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Add 7 to both sides

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Divide both sides by 3

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Now to find PN.

Based on what we know, we can assume that MP = PN. Let's make some equations!

MP = 17x-8     PN = 11x+4

17x-8 = 11x+4

Subtract 11x from both sides

6x-8 = 4

Add 8 to both sides

6x = 12

Divide by 2

x=2

Substitute 2 in for x in the equation for PN

11(2)+4

Multiply 11 by 2

22+4 = 26

PN = 26

7 0
2 years ago
Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise $400 from the play.
natima [27]
The theatre needs to sell 100 tickets in advance. or 80 tickets at the door to reach $400.  
They would need to sell 48 tickets at the door to reach their goal.


4 0
3 years ago
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