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4 years ago

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98 grams of potassium chloride are added to 217 grams of water. The volume of the water is 200 cm3. When the water reaches satur

ation, the undissolved salt is removed. If potassium chloride has a solubility of 95 g/dm3, what is the mass of the final solution?

1 answer:

IRINA_888 [86]4 years ago

5 0

Answer: -

236 g

Explanation: -

Solubility of KCl = 95 g/ dm³

Volume of the water = 200 cm³ = $\frac{200}{1000}$ = 0.2 dm³

Amount of KCl dissolved = Volume of the water x Solubility

= 0.2 dm³ x 95 g/ dm³

= 19 g

Mass of water taken = 217 g

Total mass of solution = Mass of water + Amount of KCl dissolved

= 217 g + 19 g

= 236 g

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