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xenn [34]
3 years ago
7

License plates on cars are composed of up to 7 characters. The characters can either be a digit (0,1,...,9) or an uppercase lett

er (A,B,...,Z). For example, your license plate could be: AA04R32 or S9332. (Explain your answers for each part.) (a) (3 points) How many possible license plates are there that have at least one even number and at least one vowel? (b) (3 points) Since O’s and 0’s look similar, in some states, a valid license plate cannot have both an O and a 0. How many such 7-character license plates are there? (c) (3 points) How many possible 7-character license plates are there such that the first 3 characters are 3 distinct digits in increasing order and the remaining 4 characters are 4 distinct letters in alphabetical order? (d) (3 points) There is a particular 4-letter word that is not allowed on any license plate. (Let’s pretend that the word is MATH.) How many 7-character license plates avoid the word MATH? (e) (3 points) How many different 7-character license plates avoid having 2 digits in a row?
Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

Professor Jones won't be too happy to see this.

Step-by-step explanation:

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Anastaziya [24]

Answer:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

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