Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
-7
Step-by-step explanation:
-9q = 63
q= 63/-9 = -7
Answer:
pythagorean theorem=a squared + b squared =c squared
where c is the hypotenus(the longest part)
Step-by-step explanation:
16 squared = 8 squared +....
16 ×16=256=8×8=64 + y
256_64=192
sq. root of 192=13.85
y=180_90=90
90÷2=45
y=45
z=45
x=13.85cm
hope you understand
My guess would be B.
Don't quote me on this lol.
Answer:
??
Step-by-step explanation:
