Evaluate 81.4 % of 58.81 km Give your answer rounded to 2 DP.
1 answer:
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Given:
Number of students = 35
Two out of every five boys in the club are boys.
To find:
The number of students in the club that are boys.
Solution:
Two out of every five boys in the club are boys. It means, the ratio of boys to the total number of student is 2:5.
Let the number of boys be 2x and number of students be 5x.
According to the question,
Now, the number of boys is
Therefore, 14 students in the club are boys.
Normally, we could add exponents.
however, that only is possible when the bases are the same
recall what exponents mean
12³=12*12*12
so we cannot add exponents for 12³*11³ because that means 12*12*12*11*11*11
it would not equal 12⁶ or 11⁶
or you could refer to the rule
notice when x=x then we can add the bases
fun fact below
we can reverse a previous exponential rule like this
since
then 
therefor
we can't add the exponents because the bases are not the same
however, that only is possible when the bases are the same
recall what exponents mean
12³=12*12*12
so we cannot add exponents for 12³*11³ because that means 12*12*12*11*11*11
it would not equal 12⁶ or 11⁶
or you could refer to the rule
notice when x=x then we can add the bases
fun fact below
we can reverse a previous exponential rule like this
since
therefor
we can't add the exponents because the bases are not the same
Answer:
The significance level is and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:
So we reject the null hypothesis is
Step-by-step explanation:
For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:
Null hypothesis:
Alternative hypothesis:
And the statistic is given by:
The significance level is and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:
So we reject the null hypothesis is