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satela [25.4K]
3 years ago
8

How do you factor trinomials?

Mathematics
1 answer:
gogolik [260]3 years ago
5 0
1. identify the abc... ax^2+bx+c
2. write down all the factor pairs of C
3. identify which factor pairs from the previous step sums up to letter B
4.subsitute factor pairs in 2 binomials :)
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I need to calculate a=8c-b divided by c, how do I calculate?
laila [671]

Answer:


Step-by-step explanation:

8xC-Bdivide by c


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You are ordering a pizza. You have a choice of three toppings: mushrooms, pepperoni, and peppers. How many different pizzas can
astra-53 [7]
U can do exactly 6 different pizzas
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Anyone got the answer?(^•^)
malfutka [58]

Answer:

It's 8

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16 ^{ \frac{3}{4} }  =  \sqrt[4]{16 ^{3} }  =  \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} }   = 2^{3}  = 8

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Caleb started with 50 bacteria for his science experiment and they doubled in one day. Jenna also started with 50 bacteria for h
MrRa [10]

Answer: B

Step-by-step explanation:

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4 0
3 years ago
Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com
fredd [130]

f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}

f has critical points where the derivative is 0:

2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1

The second derivative is

f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}

and f''(-1)=\frac2e>0, which indicates a local minimum at x=-1 with a value of f(-1)=\frac1e.

At the endpoints of [-2, 2], we have f(-2)=1 and f(2)=e^8, so that f has an absolute minimum of \frac1e and an absolute maximum of e^8 on [-2, 2].

So we have

\dfrac1e\le f(x)\le e^8

\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx

\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}

5 0
3 years ago
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