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LenaWriter [7]
3 years ago
10

What is the simple intrest of $1,200 at 3.5% for 2 years.

Mathematics
2 answers:
stepan [7]3 years ago
7 0
Interest = (Principle x Rate x Time in years)/100
= (1200 x 3.5 x 2)/100
= 84

The simple interest would be $84.
Lena [83]3 years ago
3 0

Answer:84

Step-by-step explanation:

I=PRT

P=1,200

R=0.035

P=2

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Which number sentence does the following number line represent A. 3+2=5 B. -3+5=2 C. 2+(-3)=5 D. 2+(-5)=-3
Vika [28.1K]
D.
It starts at 2, goes backwards 5, and ends at -3
7 0
3 years ago
What is 175% of 8000? Round to the nearest hundredth (if necessary).
igomit [66]

Answer: 175% of 8000 is equal to 14000.

Step-by-step explanation:

We know that to convert a percentage into fraction or decimal , we divide it by 100 .

Also, if find <em>x% of y</em> , then on next step we change '%' sign by \dfrac{1}{100} and  'of ' by Multiply sign (x).

Given problem : 175% of 8000

which can be re-written as: \dfrac{175}{100}\times8000

=\dfrac{175\times80}{1}\\\\=14000 (On solving)

i.e. on solving 175% of 8000, we get 14000

Therefore, 175% of 8000 is equal to 14000.

7 0
3 years ago
Neptune completes 1 1/2 truns about its axis each day.how many truns does it complete in 1 week?​
strojnjashka [21]

Answer:Fractions Word Problems – Grade 8

Solve these on a separate sheet of paper.

The following word problems may require you to add, subtract, multiply or

divide fractions.

Read each problem carefully to choose the correct operation. Some of

these are tricky! Be sure to show your work and state your answer in a

sentence!

1. The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What

fraction of games did they win?

2. In a full set of permanent teeth, ¼ of the teeth are incisors, ¼ are premolars,

and 3/8 are molars. What fraction of all the teeth are incisors, premolars and

molars?

3. Chad made a snack by combining 1/3 of a bowl of granola with ¼ of a bowl of

chopped banana and ½ of a bowl of yoghurt. Did one bowl hold all of the

ingredients at one time? Explain.

4. In the first two hockey games of the year, Rodayo played 1 ½ periods and 1

¾ periods. How many periods in all did he play?

5. Neptune completes 1 ½ turns about its axis each day. How many turns does

it complete in 1 week?

6. Shane has a piece of rope that is 7 4/5 units long. If he cuts it into pieces that

are each 3/5 of a unit long, how many pieces does he have?

7. About

4

3

of the students on the track team are girls. About

4

3

of these girls

are in grade 8. What fraction of the students on the track team are grade 8

girls?

8. Mara spent 3/5 of her vacation in British Columbia. While in that province,

she spent ½ of her time in Vancouver. What fraction of her vacation did

Michaela spend in Vancouver? If her vacation lasted 20 days, how many

days did she spend in Vancouver?

9. Nick mowed about

5

3

of the school lawn yesterday. He mowed another

4

1

of

the lawn this morning. How much is left to mow?

10. Jackie used to be on the phone

2

1

3 times as much as her brother. Her

parents threatened to take away the phone, so she cut down to

5

2

of the time

she used to be on the phone. How many times as much as her brother is

Jackie now on the phone?

Step-by-step explanation:

5 0
3 years ago
John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and
kolezko [41]

The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73  meters tall

<h3>What is a word problem?</h3>

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let <em>h </em>represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, <em>h</em> = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

Learn more about mathematics word problems?

brainly.com/question/19386917

#SPJ1

4 0
1 year ago
What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300
hodyreva [135]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30

It can be written as

2(\ln 2x)-(\ln 10x)=\ln 30         [\because \ln e^a=a]

\ln (2x)^2-(\ln 10x)=\ln 30        [\because \ln a^b=b\ln a]

\ln \dfrac{4x^2}{10x}=\ln 30        [\because \ln \dfrac{a}{b}=\ln a-\ln b]

\ln \dfrac{2x}{5}=\ln 30

On comparing both sides, we get

\dfrac{2x}{5}=30

Multiply both sides by 5.

2x=150

Divide both sides by 2.

x=75

Therefore, the correct option is B.

7 0
3 years ago
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