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Travka [436]
4 years ago
12

simplify the expression by combining like terms from highest to lowest power of the variable -5a^2 -12a-6a-4-a^2-16-18a^2+5a

Mathematics
1 answer:
Nastasia [14]4 years ago
8 0
So to start off, first combine like terms, so all the a^2 with the a^2’s, the a’s with the a’s, and the normal numbers.

Add the -5a^2, the -a^2, and the -18a^2 together.

-24a^2-12a-6a-4-16+5a

Now add the -12a, the -6a, and the 5a together.

-24a^2-13a-4-16

Lastly add the -4 and -16 together.

-24a^2-13a-20

^^That is your answer^^

Hope this helps!

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Answer:

c. 0.6

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A student cannot receive an A or a B simultaneously, so P(A \cap B) = 0.

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This means that P(A) = P(B) = 0.3

The probability that a randomly selected student from this class will receive either an A or a B equals:

This is:

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So the probability is 0.6, and the correct answer is given by option c.

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8 0
3 years ago
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1. If OQ and RT are parallel lines which statement is true?
Kaylis [27]

Answer:

Step-by-step explanation:

Question (1).

OQ and RT are the parallel lines and UN is a transversal intersecting these lines at two different points P and S.

A). ∠OPS ≅ ∠RSU [corresponding angles]

B). m∠OPS + m∠RSP = 180° [Consecutive interior angles]

C). m∠OPS + m∠OPN = 180° [Linear pair of angles]

D). Since, ∠OPS ≅ ∠TSP [Alternate interior angles]

    And m∠TSP + m∠TSU = 180° [Linear pair of angles]

Therefore, Option (A) is the correct option.

Question (2).

A). m∠RSP + m∠RSU = 180° [Linear pair of angles]

B). m∠RSP + m∠PST = 180° [Linear pair of angles]

C). ∠RSP ≅ ∠TSU [Vertically opposite angles]

D). m∠RSP + m∠OPS = 180° [Consecutive interior angles]

Therefore, Option (C) will be the answer.

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3 years ago
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PLEASE HELP ME
lukranit [14]
Give me one sec to answer be back
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