Question

Simplify completely 12x3-4x2+8x / -2x

Answer 1

$\dfrac{12x^3-4x^2+8x}{-2x}=\dfrac{12x^3}{-2x}+\dfrac{-4x^2}{-2x}+\dfrac{8x}{-2x}\\\\=-6x^2+2x-4$

Answer 2

Answer:

-6x² + 2x - 4

Step-by-step explanation:

$\frac{12x^3 - 4x^2 + 8x}{-2x}$

Step 1:

First, group the integers together and divide those:

$\frac{12}{-2}$ = -6

$\frac{-4}{-2}$ = 2 (since 4 is also a negative number, you will turn the (-) sign into a (+) sign given the rule that two negatives = a positive.)

$\frac{8}{-2}$ = -4

Step 2:

Next, group the variables and divide those (when in division, you will subtract the exponents instead of dividing):

$\frac{x^3}{x}$ = x²

$\frac{x^2}{x}$ = x (when there is only a variable and no exponent, you can assume 1 as it's exponent.)

$\frac{x}{x}$ = $x^0$ = 0

Step 3:

Combine the integers and variables in the order given and you will get:

-6x² + 2x - 4