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damaskus [11]
3 years ago
14

The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of .6 minutes. What

is the probability that a conversation lasts longer than 5 minutes? 0.04746 0.45254 0.54746 0.95254
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

0.04746

Step-by-step explanation:

To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes.  Either use a table of z-scores or a calculator with probability distribution functions.

In this case I will use my old Texas Instruments TI-83 calculator.  I select the normalcdf( function and type in the following arguments:  :

normalcdf(-100, 5, 4, 0.6).  The result is 0.952.  This is the area under the curve to the left of x = 5.  But we are interested in finding the probability that a conversation lasts longer than 5 minutes.  To find this, subtract 0.952 from 1.000:   0.048.  This is the area under the curve to the RIGHT of x = 5.

This 0.048 is closest to the first answer choice:  0.04746.

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the fifth term of an arithmetic progression is 40 and the seventh term is 28 more than the 3rd term. Find the first and 10th ter
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Answer:

Step-by-step explanation:

t5 = a + (5-1)d

t5 = a + 4d

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t3 = a + 2*d

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Start with the seventh term which has 2 equal answers

a + 2d + 28 = a + 6d                    Subtract a from both sides

2d + 28 = 6d                                Subtract 2d from both sides

28 = 4d                                         Divide by 4

28/4 = d

d  = 7

==================

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a = 40 - 28

a = 12

===================

First term is 12

10th term is

t10 = 12 + (10 - 1)*7

t10 = 12 + 9*7

t10 = 75

Interesting question. Thanks for posting

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