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damaskus [11]
3 years ago
14

The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of .6 minutes. What

is the probability that a conversation lasts longer than 5 minutes? 0.04746 0.45254 0.54746 0.95254
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

0.04746

Step-by-step explanation:

To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes.  Either use a table of z-scores or a calculator with probability distribution functions.

In this case I will use my old Texas Instruments TI-83 calculator.  I select the normalcdf( function and type in the following arguments:  :

normalcdf(-100, 5, 4, 0.6).  The result is 0.952.  This is the area under the curve to the left of x = 5.  But we are interested in finding the probability that a conversation lasts longer than 5 minutes.  To find this, subtract 0.952 from 1.000:   0.048.  This is the area under the curve to the RIGHT of x = 5.

This 0.048 is closest to the first answer choice:  0.04746.

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Hitman42 [59]

Answer:

Una ecuación de segundo grado completa es algo como:

y = a*x^2 + b*x + c

Un problema tipico que usa ecuaciones de este tipo es algo que nos haga multiplicar dos términos como h*(x + k) y n*(x + j)

Donde h, k, n, y j son números reales.

Entonces planteemos el siguiente caso.

"Juan tiene una tabla rectangular, de tal forma que su largo es (x + 3cm), y el ancho es igual a dos veces su largo, si sabemos que el área de esta tabla es 95 cm^2 ¿cuál es el valor de x?"

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En este caso tendremos:

L = (x + 3cm)

Y el ancho es dos veces eso, entonces:

W = 2*(x + 3cm)

Entonces el area de esta tabla se escribirá como:

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Entonces:

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4 0
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kolbaska11 [484]

Answer:

\frac{3}{3} * \frac{2}{3} *\frac{3}{3} =\frac{2}{3} \ in^3

====================================================

Step-by-step explanation:

The question is missing the attached figure.

The edge of each cube used to build this rectangular prism is 1/3 inch long. Based on the attached figure.

the volume of the prism = length × height × width

length = 3 * \frac{1}{3} = \frac{3}{3}

height = 3 * \frac{1}{3} = \frac{3}{3}

width = 2 * \frac{1}{3}= \frac{2}{3}

So the volume of the prism = \frac{3}{3} *\frac{3}{3} *\frac{2}{3} =\frac{2}{3} \  in^{3}

∴ The equation that shows the volume of the prism, in cubic inches

= \frac{3}{3} * \frac{2}{3} *\frac{3}{3} =\frac{2}{3} \ in^3

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