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REY [17]
4 years ago
6

24 points! need asap

Mathematics
2 answers:
Gnoma [55]4 years ago
8 0

Answer:

a. DC

b. B

c. ED

VikaD [51]4 years ago
4 0

Ray CD is the same as ray DC.

A ray with the endpoint A would be ray BA. The starting point would be point B and ending point would be A.

The opposite ray to ray EC is ray ED. The two rays are opposite to each other.

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Help please (i pressed 0.09 by mistake)
Alja [10]

Answer:

The answer should be .25

Step-by-step explanation:

The answer should be .25 because:

- there are 4 places you can score and since you want it to land on 5 and there is only one 5 it counts as a 1

- the since there are 4 in total and you want to land on 1 you get 1/4 the number one standing for there only being one 5 and the 4 standing for the number of places to land on.

-then you convert the 1/4 into a decimal which makes .25


4 0
3 years ago
Read 2 more answers
A student bought a truck with a down payment of 4000 and monthly payments of $250 for four years. What was the total cost of the
CaHeK987 [17]
4000+250(12)(4)

Down Payment plus the price per month, multiplied by the years. The total cost should be $16000.
8 0
3 years ago
Which of the following lists is ordered from least to greatest?
gladu [14]

Answer:

D

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Which of the following are solutions to 2tanx/1-tan^2x=sqrt 3?
Tanya [424]

Answer:

A, D

Step-by-step explanation:

(\frac{2tanx}{1-tan^{2}x}) =\sqrt{3} (1)

Assume that tan x = y. Replace this into the equation (1), we have:

+) \frac{2y}{1-y^{2} } =\sqrt{3}

=> 2y = \sqrt{3}  . (1 -y^{2} ) =- \sqrt{3} .y^{2}  + \sqrt{3}

=> \sqrt{3} .y^{2}  + 2y - \sqrt{3} = 0

=> \sqrt{3} . y^{2} - 1.y + 3.y - \sqrt{3} =0

=> (\sqrt{3} . y.y - 1.y) + (\sqrt{3}.\sqrt{3}  .y - \sqrt{3}) =0

=> y.(\sqrt{3} y - 1) + \sqrt{3} (\sqrt{3} y - 1) = 0

=> (y + \sqrt{3} ).(\sqrt{3} .y -1)=0

=> y + \sqrt{3} = 0 or \sqrt{3} y -1 =0

If y + \sqrt{3} = 0

=> y = - √3

=> tan x = - √3

=> x = \frac{2\pi }{3} + n.\pi with n is an integral

If \sqrt{3} y -1 =0

=> y = 1/√3

=> tan x = 1/√3

=> x = \frac{\pi }{6} + n.\pi n is an integral

So that A, D are answers.

3 0
3 years ago
Read 2 more answers
On our math test, I made two complementary angles; one of the angles is 26 ̊more than the other. Identify the angles.
iogann1982 [59]
So,

Let x represent the first angle and y represent the second angle.

x + y = 90
x = y + 26

Substitute
y + 26 + y = 90

Collect Like Terms
2y + 26 = 90

Subtract 26 from both sides
2y = 64

Divide both sides by 2
y = 32

Substitute
x = 32 + 26
x = 58

Check
58 + 32 = 90
90 = 90 This checks.

58 = 32 + 26
58 = 58 This also checks.

The measure of one angle is 58° and the measure of the other angle is 32°.
6 0
3 years ago
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