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hram777 [196]
4 years ago
11

Which pair of elements is MOST likely to chemically combine and form ionic bonds?. A). chlorine and chlorine. B). lithium and ch

lorine. C). carbon and hydrogen. D). sulfur and oxygen
Chemistry
2 answers:
Feliz [49]4 years ago
5 0
The pair of elements that will most likely combine chemically to form ionic bonds are B. Lithium and Chlorine.
Dahasolnce [82]4 years ago
3 0

Answer: B). lithium and chlorine

Explanation: An ionic bond is formed between a metal and a non-metal by transfer of electrons from metal to non metal.

Electronic configuration of lithium:

[Li]:31s^22s^1

Lithium atom will loose one electron to gain noble gas configuration and form lithium cation with +1 charge.

[Li^+]=1s^22s^2

Chlorine atom has oxidation number of -1.

Electronic configuration of chlorine;

[Cl]=1s^22s^22p^63s^23p^5

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

[Cl^-]=1s^22s^22p^63s^23p^6

Li^+ combine with Cl^- to form lithium chloride (LiCl)

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3 0
3 years ago
If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density
adelina 88 [10]

Explanation:

The given data is as follows.

      Mass = 27.9 g/mol

As we know that according to Avogadro's number there are 6.023 \times 10^{26} atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

            1 atoms weight = \frac{38}{6.023 \times 10^{26}}    

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

            = \frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}

            = 37.06 \times 10^{-26}

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

                   = a^{3}

                   = (0.503 \times 10^{-9})^{3}

                   = 0.127 \times 10^{-27} m^{3}

Formula to calculate density of diamond cell is as follows.

               Density = \frac{mass}{volume}

                             = \frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}

                            = 2918.1 g/m^{3}

or,                         = 0.0029 g/cc       (as 1 m^{3} = 10^{6} cm^{3})

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0
3 years ago
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