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3 years ago

What is the name for BrCl4

Chemistry

1 answer:

egoroff_w [7]3 years ago

5 0

Answer:

<h3>Other names: BRCL4 MUTATIONS COPY NUMBER COMPOUND SENSITIVITY RNA INTERFERENCE GENE EXPRESSION SIMILAR CELL LINES Cell line BrCL4</h3>

Explanation:

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What is the total number of valence electrons in the lewis structure of sebr2o?

zloy xaker [14]

Answer:

15.4: Lewis Structures: Counting Valence Electrons

Explanation:

3 0

2 years ago

Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.

marta [7]

Answer:

Approximately $53.3\; \rm g$ .

Explanation:

Lookup Avogadro's Number: $N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}$ (three significant figures.)

Lookup the relative atomic mass of $\rm H$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm H$ : $1.008$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

(For example, the relative atomic mass of $\rm H$ is $1.008$ means that the mass of one mole of $\rm H\!$ atoms would be approximately $1.008\!$ grams on average.)

The question counted the number of $\rm H_2SO_4$ molecules without using any unit. Avogadro's Number $N_{\rm A}$ helps convert the unit of that count to moles.

Each mole of $\rm H_2SO_4$ molecules includes exactly $(1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}$ of these $\rm H_2SO_4 \!$ molecules.

$3.27 \times 10^{23}$ $\rm H_2SO_4$ molecules would correspond to $\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol$ of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of $\rm H_2SO_4$ gives the mass of each mole of $\rm H_2SO_4\!$ molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

$\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the mass of approximately $0.541389\; \rm mol$ of $\rm H_2SO_4$ :

$\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}$ .

(Rounded to three significant figures.)

6 0

3 years ago

PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!!

Pepsi [2]

Answer:8

Everything after the decimal place is a significant figure here

5 0

4 years ago

Which of the following is NOT true?

ivanzaharov [21]

B, hope this helps :)

4 0

3 years ago

Read 2 more answers

Laughing gas, N2O, also known as nitrous oxide contains 28.01 g of nitrogen in every 44.01 g of nitrous oxide. What mass of nitr

Sav [38]

Answer : The mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.

Explanation :

As we are given that, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide. Now we have to determine the mass of nitrous oxide formed from 85.20 g of nitrogen.

As, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide

So, 85.20 g of nitrogen is present in $\frac{85.20}{28.01}\times 44.01=133.9g$ of nitrous oxide

Thus, the mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.

4 0

3 years ago