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Wewaii [24]
3 years ago
14

What is the name for BrCl4

Chemistry
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

<h3>Other names: BRCL4 MUTATIONS COPY NUMBER COMPOUND SENSITIVITY RNA INTERFERENCE GENE EXPRESSION SIMILAR CELL LINES Cell line BrCL4</h3>

Explanation:

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What is the mass number of an isotope with an atomic number of 57 and that has 69 neutrons?
Karolina [17]

Answer:

mass number=126

Explanation:

57+69=126

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With respect to the categories of assets, liabilities, and stockholders' equity presented on the balance sheet (statement of fin
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Explanation:

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4 0
3 years ago
Explain the difference between cocl2 6h2o and anhydrous cobalt chloride
lana66690 [7]
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8 0
3 years ago
when the following redoc reaction is balances (assume acidic solution), how many moles of water appear and on what side
PolarNik [594]

8 moles of water on the right side.

An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).

Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.

Step 1:

MnO4- ----> Mn2+

2Cl- ------> Cl2

Step 2:

MnO4- --> Mn2+ + 4H2O

2Cl- -----> Cl2

Step 3:

8H+ + MnO4- ------> Mn2+ + 4H2O

2Cl- ----->Cl2

Step 4:

8H+ + MnO4- +5e- ------>Mn2+ + 4H2O

2Cl- ----> Cl2+ 2e-

Step 5:

16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2

This is the balanced equation in an acidic medium.

That is 8, right side.

To know more about redox reaction follow the link:

https://brainly.in/question/9854479

#SPJ4

8 0
1 year ago
Derivative for tan(x)
Maksim231197 [3]

Answer:

  • sec² (x)

Explanation:

Use the trigonometric ratio definition of the tangent function and the quotient rule.

  • tan(x) = sin(x) / cos(x)

Quotient rule: the derivative of a quotient is:

  • [the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²

  • (f/g)' = [ g×f' - f×g'] / g²

So,

  • tan(x)' = [ sin(x) / cos(x)]'
  • [ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²

                                   = [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²

                                   = [ cos²(x) + sin²(x) ] / cos²(x)

                                   = 1 / cos² (x)

                                   = sec² (x)

The result is that the derivative of tan(x) is sec² (x)

4 0
3 years ago
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