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yan [13]
3 years ago
14

Which fraction expresses 36/80 in lowest terms? A. 9/20 B. 18/40 C.4/5 D. 18/20

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0
To solve this problem, we need to factor 36 and 80, then find greatest common factor, and divide numerator and denominator by this greatest common factor.
36/80 = (4*9)/(4*20)= 9/20

Answer A. 9/20.

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\[f(x)=\sqrt{x ^4-16x ^{2}}\]
marusya05 [52]
f ( x ) =  \sqrt{ x^{4} -16 x^{2} }
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )
b ) f ` ( x ) = \frac{1}{2 \sqrt{x ^{4}-16 x^{2}  } } *  ( x^{4}-16 x^{2} )` =
= ( 2 x³ - 16 x ) / √(x^4 - 16 x²)
c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34 
4 0
3 years ago
Kevin drove 357 miles using 14 gallons of gas. At this rate, how many miles would he drive using 16 gallons of gas?​
Inessa [10]

Answer:

Kevin could drive 408 miles using 16 miles of gas.

Step-by-step explanation:

357 (1/14) = 25.5

25.5 (16) = 408

7 0
3 years ago
What is the equation of a line with a slope of ​3​ and a point (3, 1) on the line?
dem82 [27]
The answer is:
y = 3x - 8 

Find b by plugging in the point (x,y) which is (3,1).
1= 3(3)+b
1= 9 + b
-8 = b
5 0
3 years ago
Read 2 more answers
If f(x)=5fx3-2 and g(x)=x+1, find (f-g)(x)
kirza4 [7]

Answer:

5x^3-x-3

Step-by-step explanation:

5x^3-2-x-1

5x^3-x-3

3 0
3 years ago
For 1983 through 1989, the per capita consumption of chicken in the u.S. Increased at a rate that was approximately linear. In 1
Volgvan

We have been given that in 1983, the per capita consumption was 39.7 pounds, and in 1989 it was 47 pounds.

Let us assume t=0 corresponds to year 1980.

Hence, we can express the given information as ordered pairs as (3,39.7) and (9,47).

We can to find a linear function passing through these points. Let us first find slope of the linear function:

m=\frac{y_{2}-y_{1} }{t_{2}-t_{1}} =\frac{47-39.7}{9-3} =\frac{7.3}{6} =\frac{73}{60}

We can write the required linear function as:

y-39.7=\frac{73}{60}(t-3)

Upon simplifying  this, we get:

y=\frac{73}{60}t+\frac{721}{20}

In order to find per capita consumption in 1995, we need to substitute t=15 in this function.

y=\frac{73}{60}(15)+\frac{721}{20}=54.3

Therefore, we would expect the per capita consumption of chicken in 1995 to be 54.3.

3 0
4 years ago
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