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3 years ago

Question 13 PLEASE HELP find the x-intercepts of -x+2y=6 X-intercept:(____,0). Type only the value that fills one the blank

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

Step-by-step explanation:

to be honest I'm not sure how

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If P=Q^R , Q=R^P , R=P^Q.<br>Then Prove: P×Q×R=1.

8_murik_8 [283]

Answer:

PQR=1

Step-by-step explanation:

5 0

3 years ago

Please help im stuck

agasfer [191]

Answer:

Area of field = 10 cm²

Step-by-step explanation:

Given field is a trapezium;

Parallel sides of given field are; 1¹/₂ cm and 3¹/₂ cm

Height of trapezium = 4 cm

Find:

Area of field

Computation:

Area of field = Area of trapezium

Area of trapezium = [Sum of Parallel sides / 2][h]

Area of field = [(1¹/₂ + 3¹/₂) / 2][4]

Area of field = [(5) / 2][4]

Area of field = [2.5][4]

Area of field = 10 cm²

8 0

2 years ago

Which ordered pair represents a point on a line y = 2x +1. a. 0,3 b. 1,2 c. 2,1 d. -1,-1.

Drupady [299]

D. -1,-1 because If you were to place that on a graph you would get d. for your answer and you can also do it on a TI-83 plus calculator

4 0

2 years ago

What is the slope of the line passing through the points (2 5) and (-1 -4)

Elan Coil [88]

Answer:

x1 y1 x2 y2

(2 5) (-1 -4)

slope m = (y2-y1)/(x2-x1)

( -4 -5 )/( -1 -2 )

( -1/ -1 )

m= -1/-1

Step-by-step explanation:

pls Mark me as brainleast and folow me

3 0

3 years ago

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

3 0

2 years ago