depends on the tension and the length of the rope
20 cats * ( 1 bag of food / 5 cats per month ) = 4 bags of food per month to feed all 20 cats
Complete Question
A survey is planned to estimate the proportion of voters who support a proposed gun control law. The estimate should be within a margin of error of ±5% with 90% confidence, and we do not have any prior knowledge about the proportion who might support the law. How many people need to be included in the sample?
Round your answer up to the nearest integer.
sample size = _____
Answer:
The sample size is
Step-by-step explanation:
From the question we are told that
The margin of error is E = 5% = 0.05
Generally given that there was no prior knowledge about the proportion of who might support the law, we will assume the sample proportion to be

From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the sample size is mathematically represented as
=>
=>
Answer:
StartFraction 24 Over 65 EndFraction
Step-by-step explanation:
Total number of students = 26
Number of boys = 10
Number of girls = 26-10
=16
Eduardo has to pull two names out of the hat without replacing them.
First name
Probability= Favourable outcome/Total outcome
Probability of girls=16
Total probability=26
Eduardo has to pull two names out of the hat without replacing them.
Probability= Favourable outcome/Total outcome
=16/26
=8/13
For the second name:
Without replacement of the first hat
Probability of girls=16-1=15
Total probability=26-1=25
Probability= Favourable outcome/Total outcome
=15/25
=3/5
Probability of both of Eduardo's partner for the group project will be girls=8/13*3/5
=24/65
StartFraction 24 Over 65 EndFraction
Answer:
5
Step-by-step explanation:
Hopebthis helps it ahowed right for me