All categories

3 years ago

Which number below is 9 a common factor of 16 and 20?

1 answer:

7 0

SOLUTION:

Highest common factor of 16 and 20 which is also below 9 is 4.

HCF of 16 and 20 = 4

Hope this helps! :)
Have a lovely day! <3

You might be interested in

PART1

Mice21 [21]

Part 1: $\frac{5x^{3} + 10x^{2} + 15x}{5x} = \frac{5x^{3}}{5x} + \frac{10x^{2}}{5x} + \frac{15x}{5x} = x^{2} + 2x + 3$
The answer is C.

Part 2: $\frac{3x^{4} + 5x^{2} + 2x}{x} = \frac{3x^{4}}{x} + \frac{5x^{2}}{x} + \frac{2x}{x} = 3x^{3} + 5x + 2$
The answer is A.

8 0

3 years ago

The area of the rectangular sandbox at Dave's school is 117 square feet. The sandbox has a width of 9 feet as shown in the diagr

Annette [7]

Answer:

ay bru ima tell yu dhis rn is c

Step-by-step explanation:

4 0

2 years ago

Change 7.5m into mm.<br><br> What’s the answer to this?

liubo4ka [24]

7500
the way is multiply the length value by 1000

4 0

2 years ago

Read 2 more answers

What does point p on the number line represent

Yuki888 [10]

Point p on the number line represents, -7

4 0

2 years ago

Read 2 more answers

A. Student GPAs: Bob’s z-score z = + 1.71 μ = 2.98 σ = 0.36 b. Weekly work hours: Sarah’s z-score z = + 1.18 μ = 21.6 σ = 7.1 c.

hjlf

Answer:

a) $x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

b) $x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

c) $x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.71, \mu = 2.98,\sigma = 0.36$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

Part b

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.18, \mu = 21.6,\sigma = 7.1$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

Part c

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = -1.35, \mu = 150,\sigma = 40$

If we solve for x from the z score formula we got:

$x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

5 0

3 years ago