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Elina [12.6K]
3 years ago
5

t{Question:}" align="absmiddle" class="latex-formula">
Please help me with my homework.
Here's the math problem:
\huge\bold{(2a^{2} )^{2} (bc^{2} )^{3} }
Due today. Please do not spam.
Mathematics
2 answers:
galina1969 [7]3 years ago
5 0

\sf \: ( {2a}^{2} )^{2} (bc^{2} )^{3}

To raise a product to a power, raise each factor to that power

\sf \:  {4a}^{4}  {b}^{3}  {c}^{6}

<h3>We have used the following laws of exponents here⤵️</h3>

  • \tt \: a^{m}  \times  {a}^{n}  =  {a}^{m + n}
  • \tt \: ( {a}^{m} )^{n}  =  {a}^{m \times n}

Kitty [74]3 years ago
3 0

4 {a}^{4} {b}^{3} {c}^{6} is the answer.

Explanation :-

Hey there

Lets solve this :-

(2 {a}^{2})^{2}(bc^{2})^{3}

=  >  {2}^{2} \times (a^{2} )^{2}b^{3}( {c}^{2})^{3}

=  > 4( {a}^{2})^{2} {b}^{3}(c^{2})^{3}

4 {a}^{4} {b}^{3} {c}^{6}

Therefore 4 {a}^{4} {b}^{3} {c}^{6}is the answer

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babunello [35]

Answer:

Therefore the THREE roots are

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Step-by-step explanation:

Given:

x^{3}+7x^{2} +12x= 0

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Solution:

As the degree of the polynomial is THREE then the number of root are also THREE.

x^{3}+7x^{2} +12x= 0\\\\x(x^{2}+7x +12)= 0\\\\x=0\\or\\x^{2}+7x +12= 0\\

Now one root is Zero For other we need to Factorize

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8 0
3 years ago
I neeed helppp please due today
rjkz [21]

Step-by-step explanation:

y=x+6.......(1)

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