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Inga [223]
3 years ago
13

Factor each polynomial x2-36

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0
(x+6)(x-6) would be the factored form
34kurt3 years ago
5 0

I only see the polynomial x^2-36, so I'll factor that one.

We can use two approaches: the most "standard" one requires us to find the roots of the polynomial. Then, for each root x_i we write the factor (x-x_i), and decompose the polynomials like this:

x^2-36=0 \iff x^2 = 36 \iff x = \pm\sqrt{36} = \pm 6

So, the root 6 yields the factor (x-6), and the root -6 yields the factor (x+6). This means that the polynomial can be factored as

x^2-36 = (x+6)(x-6)

Alternatively, you can observe that the polynomial comes in the form a^2-b^2, and it can be factored as

a^2-b^2 = (a-b)(a+b)

which again leads to

x^2-36 = (x)^2 - (6)^2 = (x+6)(x-6)

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A jar containing only nickels and dimes contains a total of 60 coins. The value of all the coins in the jar is $4.45. Solve by e
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Answer: 31 nickels and 29 dimes

<u>Step-by-step explanation:</u>

Nickels (.05): x

Dimes (.10): y


 Value:     .05x + .10y = 4.45 →  -20(.05x + .10y = 4.45)   →   -x - 2y = -89

Quantity:        x  +    y  = 60   →       1(x  +    y  = 60)           →   <u> x  + y </u> = <u> 60 </u>

                                                                                                       -y  = -29

                                                                                                        y  =  29

Next, substitute "29" for "y" into either equation and solve for "x":

x +  y  = 60

x + 29 = 60

x          = 31


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schepotkina [342]
The answer is B(11, 2sqrt(12) )
proof

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</span>and the circle passes through the point (-5,2) so we can write 
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and  for <span>B(11, 2sqrt(12) )     </span>11²+  (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
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