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dolphi86 [110]
3 years ago
15

I have 3 digits. If I round to the nearest hundred, I am 200. Multiply my ones digit by 2 and you get my tens digit. Both my one

s and tens digits are even.
Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

the answer is 393

Step-by-step explanation:

hope we can be friends

can i please get brainliest

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Help! 10 Points not 5!
KATRIN_1 [288]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

__

The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

6 0
3 years ago
What is the mode of the following numbers? 6,4,1,9,3,8,3,5,10
siniylev [52]

Answer:

Step-by-step explanation:

Mode is the number that appears most often in a set, so for this one the mode would be 3 since it appears the most often

7 0
3 years ago
17 which equation has the same solutions as x6x-750?1) (x+3) 213)
Ilya [14]
Hello,

x²+6x-7=0
==>x²+2*3x+3²-9-7=0
==>(x+3)²-16=0

Answer D

8 0
3 years ago
An odd number between 301 and 370 has three different digits. If the sum of its digits is five times the hundreds digit, find th
damaskus [11]
For the answer to the question above, <span> 
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
5 0
3 years ago
What is the answer pls
Anon25 [30]

Answer:

7.375 ib.

Step-by-step explanation:

You just add it all together

3 0
2 years ago
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