9514 1404 393
Answer:
18
Step-by-step explanation:
Solve the first for a, then substitute into the second.
a = 27/(5b^2)
Then ...
(27/(5b^2))^2·b = 135
27^2/(5^2·135) = b^3 = 27/125
b = ∛(27/125) = 3/5
a = 27/(5(3/5)^2) = 15
__
The expression of interest is ...
a +5b = 15 + 5(3/5) = 15 +3
a +5b = 18
Answer:
Step-by-step explanation:
Mode is the number that appears most often in a set, so for this one the mode would be 3 since it appears the most often
Hello,
x²+6x-7=0
==>x²+2*3x+3²-9-7=0
==>(x+3)²-16=0
Answer D
For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
Answer:
7.375 ib.
Step-by-step explanation:
You just add it all together
