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viva [34]
3 years ago
15

Which tab provides commands for the most commonly used elements in Word Software?

Computers and Technology
1 answer:
Flauer [41]3 years ago
6 0
I think it should be in the design tab
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Explain how loops can be utilized in list processing. Please provide Python examples in your response.
Dominik [7]

Answer:

data = [0,1,2,3,4]

for i in range(4):

   print(data[i])

   i+=1

Explanation:

Loops can be utilized in a listing process by looping back to a list with a variable while the loop increases that variable to give a different response from the list.

8 0
2 years ago
Para que se utiliza openoffice en la vida cotidiana?
Mama L [17]
OpenOffice se utiliza para organizar y presentar los datos o la información de otra manera.

espero y te ayude! : )
3 0
3 years ago
Read 2 more answers
The following SQL statement contains which type of subquery? SELECT title FROM books WHERE EXISTS (SELECT isbn FROM orderitems W
Rudiy27

Answer:

(a) Correlated.

Explanation:

Correlated subquery :These sub queries reference columns from outer table or uses values from outer query.These sub queries are processed atleast once for every row processed.So because of this reason correlated sub queries can be slow.Since the query in the question also uses value from the outer query so it is a correlated query.

4 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
In one week, your company received the following quantities of e-mail messages. Monday 240 Tuesday 315 Wednesday 290 Thursday 18
Vika [28.1K]

Answer:

280

Explanation:

Average = (240 + 315 + 290 + 180 + 375) ÷ 5

= 1400 ÷ 5

= 280

Cheers

3 0
3 years ago
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