Answer:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
Explanation:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
Decrease. Think like this, if you were standing in the ocean getting hit by waves, frequency would be how many waves hit you in a certain amount of time. If there were lots of little waves hitting you the number of waves (the frequency) would be high, whereas big waves are slower and take more time to reach you so you would get hit by less of them in the same time frame. The less frequent, the longer the wave.
Answer:
The importance of saving money is simple: It allows you to enjoy greater security in your life. If you have cash set aside for emergencies, you have a fallback should something unexpected happen. And, if you have savings set aside for discretionary expenses, you may be able to take risks or try new things.
Answer:
Here the code is given as follows,
Explanation:
Code:-
#include <stdio.h>
int isSorted(int *array, int n) {
if (n <= 1) {
return 1;
} else {
return isSorted(array, n-1) && array[n-2] <= array[n-1];
}
}
int main() {
int arr1[] = {3, 6, 7, 7, 12}, size1 = 5;
int arr2[] = {3, 4, 9, 8}, size2 = 4;
printf("%d\n", isSorted(arr1, size1));
printf("%d\n", isSorted(arr2, size2));
return 0;
}
Output:-
I don't understand the You tube part, but uh yeah???
