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2 years ago

10

tara has a large box of dog treats that weighs 6.6 pounds. she uses the large box of dog treats to make smaller bags, each conta

ining 0.6 pound of treats.

1 answer:

storchak [24]2 years ago

3 0

Answer:

11

Step-by-step explanation:

6.6/0.6 = 66/6 = 11

You might be interested in

Shapes A and B are similar.

kari74 [83]

The scale factor from A to B is 5/3 and the value of r is 33/5

<h3>The scale factor from A to B</h3>

From the figure, we have the following corresponding sides

A : B = 5 : 3

Express as fraction

B/A = 3/5

This means that, the scale factor from A to B is 5/3

<h3>The value of r</h3>

From the figure, we have the following corresponding sides

A : B = 11 : r

Express as fraction

B/A = r/11

Recall that:

B/A = 3/5

So, we have:

3/5 = r/11

Multiply by 11

r = 33/5

Hence, the value of r is 33/5

Read more about similar shapes at:

brainly.com/question/14285697

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3 0

1 year ago

Answer this <br> then i will mark u as brainliest

sashaice [31]

Answer:

A, it will decrease by 90.

Step-by-step explanation:

If the number is 92,320 and you interchange 2 and 3, you would get 92,230. 320-230 equals 90, therefore giving you the answer.

5 0

1 year ago

Given sec theta=-4/3 and 90

KATRIN_1 [288]

What is ur question?

8 0

3 years ago

Which number line correctly represents the irrational numbers listed below

dimaraw [331]

Answer:

D

Step-by-step explanation:

bc it starts with -square root of 20 and then - square root of 6 and the 3.14 and then square root of 8 and then square root of 18

4 0

2 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

2 years ago