What is the least common multiple of 11 and 19

Round 75.6475.6475, point, 64 to the nearest ten

Maru [420]

Answer: nearest tenth is 49.0

Step-by-step explanation:

Hope this helps!

7 0

3 years ago

6+(-4 3/4)+(-2 1/8)<br> Fraction in simplest form

Bas_tet [7]

Answer:

6-43/4-21/8

6(-68-21/8)

48-107/8

-59/8

4 0

3 years ago

Let x² + 15x = 49 . What values make an equivalent number sentence after completing the square? Enter your answers in the box

Pavlova-9 [17]

Answer:

Step-by-step explanation:

15/2 = 7.5 and (7.5)^2 = 56.25 so

x^2 + 15x + 56.25 = 49 + 56.25

x^2 + 15x + 56.25 = 105.25.

5 0

3 years ago

Read 2 more answers

MCR3U1 Culminating 2021.pdf

11111nata11111 [884]

Answer:

(a) $y = 350,000 \times (1 + 0.07132)^t$

(b) (i) The population after 8 hours is 607,325

(ii) The population after 24 hours is 1,828,643

(c) The rate of increase of the population as a percentage per hour is 7.132%

(d) The doubling time of the population is approximately, 10.06 hours

Step-by-step explanation:

(a) The initial population of the bacteria, y₁ = a = 350,000

The time the colony grows, t = 12 hours

The final population of bacteria in the colony, y₂ = 800,000

The exponential growth model, can be written as follows;

$y = a \cdot (1 + r)^t$

Plugging in the values, we get;

$800,000 = 350,000 \times (1 + r)^{12}$

Therefore;

(1 + r)¹² = 800,000/350,000 = 16/7

12·㏑(1 + r) = ㏑(16/7)

㏑(1 + r) = (㏑(16/7))/12

r = e^((㏑(16/7))/12) - 1 ≈ 0.07132

The model is therefore;

$y = 350,000 \times (1 + 0.07132)^t$

(b) (i) The population after 8 hours is given as follows;

y = 350,000 × (1 + 0.07132)⁸ ≈ 607,325.82

By rounding down, we have;

The population after 8 hours, y = 607,325

(ii) The population after 24 hours is given as follows;

y = 350,000 × (1 + 0.07132)²⁴ ≈ 1,828,643.92571

By rounding down, we have;

The population after 24 hours, y = 1,828,643

(c) The rate of increase of the population as a percentage per hour = r × 100

∴ The rate of increase of the population as a percentage = 0.07132 × 100 = 7.132%

(d) The doubling time of the population is the time it takes the population to double, which is given as follows;

Initial population = y

Final population = 2·y

The doubling time of the population is therefore;

$2 \cdot y = y \times (1 + 0.07132)^t$

Therefore, we have;

2·y/y =2 = $(1 + 0.07132)^t$

t = ln2/(ln(1 + 0.07132)) ≈ 10.06

The doubling time of the population is approximately, 10.06 hours.

8 0

3 years ago

According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 in

Zolol [24]

Answer:

The probability that the person is between 65 and 69 inches is 0.5403

Step-by-step explanation:

Mean height = $\mu = 66$

Standard deviation = $\sigma = 2.5$

We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)

$Z=\frac{x-\mu}{\sigma}$

At x = 65

$Z=\frac{65-66}{2.5}$

Z=-0.4

Refer the z table for p value

P(x<65)=0.3446

At x = 69

$Z=\frac{69-66}{2.5}$

Z=1.2

P(x<69)=0.8849

So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403

Hence the probability that the person is between 65 and 69 inches is 0.5403

6 0

3 years ago