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Nastasia [14]
4 years ago
13

Unit 1: Scientific Notation Constructed Response Assignment

Mathematics
1 answer:
balu736 [363]4 years ago
5 0
brainly.com/question/5027087

Let C, S and H be the diameters of cell, sand and hair


Diameter of a cell: C=1 \cdot 10^{-5}m

Diameter of a grain of sand: S=2 \cdot10^{-4}m

Part A:

H=0.000025=2.5 \cdot 10^{-5} meters, because it takes 5 movements right of the decimal dot, until there is only one digit to its left.

Part B:

we are comparing S=2 \cdot10^{-4} m to C=1 \cdot10^{-5} m ,

\frac{S}{C}= \frac{2 \cdot 10^{-4}}{1 \cdot 10^{-5}}=\frac{20 \cdot 10^{-5}}{1 \cdot 10^{-5}}=20

thus S is 20 times larger than C

Part C

1m=1 \cdot10^9nm

thus,

H=2.5 \cdot 10^{-5}m=2.5 \cdot 10^{-5} \cdot 1 \cdot 10^9nm=2.5 \cdot 10^{-5+9}=2.5\cdot10^4nm

Part D.

1m=1\cdot 10^9nm\\\\1nm=\displaystyle{ \frac{1m}{10^9}=1\cdot 10^{-9}m}

thus 300 nm are written in meters as follows:

300nm= 300\cdot 1\cdot 10^{-9}m=3\cdot 10^2 \cdot 10^{-9}m=3\cdot 10^{-7}m
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Step-by-step explanation:

If you have any questions feel free to ask in the comments.

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a photograph is printed in the center of a piece of paper measuring 7 cm by (x + 8) cm. The photo measures 5 cm by (x +6) cm . T
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The paper is 7 cm by (x + 8) cm.

A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.

The area of the border/space around the photo is 50 cm².


To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.


The area of the paper:

A = 7 · (x + 8)


The area of the photo:

A = 5 · (x + 6)


Your equation to find the area of the border around the photo is:

(7 · (x + 8)) - (5 · (x + 6)) = A

[area of paper - area of photo = area of border]


Since you know the area of the border, you can plug it in:

(7 · (x + 8)) - (5 · (x + 6)) = 50


Multiply the 7 into (x + 8), and multiply the 5 into (x + 6)

(7x + 56) - (5x + 30) = 50


Distribute/multiply the - to (5x + 30)

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Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
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Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

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Longitud = 11 + 4 = 15

3r rectangle:

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