Using 5 letters followed by 2 digits, how many passwords are possible?
1 answer:
Since there is no condition whatsoever for this arrangement, I can consider the 2 digits and the 5 letters as 7 different objects.
Total permutation (with no repetition):
7 chosen among 7 , that is 7 ! = 5040 arrangements
Total permutation (WITH REPERTITION):
7⁷ = 823 543
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