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3 years ago

15

Help with a function graph? Please!?

1 answer:

GaryK [48]3 years ago

7 0

We notice that as you go from -5 to 0, the line is continuously decreasing. Here we say that in the interval (-5, 0) the function is "decreasing".

Similarly, as we go (in x) from 0 to 4, the line goes up. Here we say that the function is increasing in (0, 4).

In [-8, -5) and [4, 8) the line is "constant", so no increase or decrease at any point.

Using a square bracket " [ " indicates that the endpoint is included, while a " ( " indicates it is not.

When we indicate increasing or decreasing intervals the endpoints are always open, that is, not included. This is a subtle point related to a later concept.

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The number of members over time in an online music sharing club can be modeled by an exponential function. the club started with

Paraphin [41]

Answer:

a.) $N(x) = N_{0} e^{bx}$

b.) therefore b = $\ln \frac{2142}{2100} = \ln (1.02) = 0.0198$

b is the rate of increase of number of members

c.) The club will not be able to get more than 5000 members during its first year.

Step-by-step explanation:

i) the club started with 2100 members.

so we can write $N_{0}$ = 2100.

a.) so we can write the equation as an exponential function given by

$N(x) = N_{0} e^{bx}$ where x is in months and b is a constant and N(x) is the number of members in the online music sharing club .

therefore 2142 = 2100 $\times (e^{b\times 1})$ = 2100 $e^{b}$

b.) therefore b = $\ln \frac{2142}{2100} = \ln (1.02) = 0.0198$

b is the rate of increase of number of members

c.) Will the club have more than 5000 members during its first year? Justify your reasoning.

5000 = 2100 $e^{0.0198x}$

therefore x = $\frac{1}{0.0198} \ln{(\frac{5000}{2100} )} = 43.81 \hspace{0.1cm}months$

The club will not be able to get more than 5000 members during its first year.

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2 years ago

What is the slope of the line shown in the graph? (4 points)

Korvikt [17]

Answer:

a. or $\frac{3}{-2}$

Step-by-step explanation:

Slope is equal to y1-y2 over x1-x2.

So the equation would be:

$\frac{2-(-1)}{-3-(-1)}$

2-(-1)=2+1=3

-3-(-1)=-3+1=-2

So the answer is:

$\frac{3}{-2}$

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