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kirill115 [55]
3 years ago
6

An accounting professor wishing to know how many MBA students would take a summer elective in international accounting did a sur

vey of the class she was teaching. Which kind of sample is this? A) Convenience sample B) Cluster sample C) Systematic sample D) Simple random sample
Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0

Answer: B) Convenience Sample

Step-by-step explanation:

A convenience sample is used when pilot testing is to be done. In this case, the accounting professor wishes to know who would take a elective. Since this involves taking sample from part of population that is near at hand and can be easily taken. So it is a convenience sample.

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3/8 of 24 is equal to?​
o-na [289]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
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Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
Which two steps could be taken to simplify the expression y/3 + 2 = 11?<br>​
IRINA_888 [86]

Answer:

y = 27

Step-by-step explanation:

y/3 + 2 = 11

First subtract 2 from each side

y/3 + 2-2 = 11-2

y/3  = 9

Then multiply each side by 3

y/3 *3 = 9*3

y = 27

8 0
3 years ago
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PLEASE HELP ASAP 25 PTS + BRAINLIEST OR RIGHT/BEST ANSWER
Snowcat [4.5K]

down 3 unit mean -3 outside root

right 2 unit mean -2 inside root,

so the answer is

y =  \sqrt{x - 2}  - 3

8 0
3 years ago
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Solve the following equation by factoring. <br><br> 2x2−7x+3=0
slava [35]

Answer:

x=3

Step-by-step explanation:

Step 1: Factor left side of equation.

(2x−1)(x−3)=0

Step 2: Set factors equal to 0.

x−3=0

ANSWER:

x=3

8 0
3 years ago
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