1. 8/9 ÷ 4/9 is done by inverting the divisor (4/9) and then multiplying:
(8/9)(9/4) = 8/4 = 2 (answer)
2. 1/3 ÷ 6 is done similarly: (1/3)(1/6) = 1/18 (answer)
3. 4 ÷ 1/5 = 4 * 5 = 20 (answer)
4. 7 1/2 ÷ 1/4 = (15/2)(4/1) = 30 (answer)
Answer:
<em>The car will worth $15815 after 5 years.</em>
Step-by-step explanation:
The formula is: 
, where P = Initial cost, A = Final cost, r = Rate of change in cost per year and t = Number of years.
Here, 
and 
As here the <u>value of the car depreciates every year, so we need to plug the value of 
as negative</u>. So, 
Now plugging the above values into the formula, we will get.....
<em>(Rounded to the nearest dollar)</em>
So, the car will worth $15815 after 5 years.
Answer:
p(t) = 0.19e0.10t
=>p'(t) = 0.19e0.10t (0.10*1)
=>p'(t) = 0.019e0.10t
t = 0 represents 1994
for 2002, t=2002-1994 =8
in 2002
average price =p(8)
=>average price = 0.19e0.10*8
=>average price =0.422853... million
rate of increase =p'(8)
=>rate of increase = 0.019e0.10*8
=>rate of increase =0.0422853... million per year
p(8)=$ 0.42 million
p'(8)=$ 0.042 million per year
The first problem, all you need to do is combine like terms then isolate the n:
4n-2n=4
~subtract 2n from 4n (2n)
2n=4
~then divide both sides of the equation by 2 to isolate the n
n=4
The second problem follows the same steps of combining like terms and isolating the variable. Here, you'll have to combine 2 like terms:
-12=2+5v+2v
~first combine the variables which is just 5v+2v which is 7v
-12=2+7v
~then subtract 2 from both sides to isolate the 7v
-14=7v
~then divide both sides by 7 to isolate the v and get your answer
-2=v
Hope that helped!
I: y<2*x
II: y<8
III: x>2
a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution
b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution
c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution
d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution
e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution
f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution
so a,b,c,e are solutions and d,f not
