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Natasha2012 [34]
3 years ago
7

Vroom Vacuums sells the Tornado vacuum cleaner. Each Tornado has a one-year warranty that covers any product defects. When custo

mers purchase a Tornado, they also have the option to purchase an extended three-year warranty that covers any breakage or maintenance. Customers pay 20% less for the extended warranty if they buy it at the same time they buy a Tornado. How many performance obligations exist in the implied contract for the purchase of a vacuum cleaner
Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0

Answer:

Performance obligation:

Revenue is recognized by a company if the contractual obligations are satisfied by transferring the goods and services to a customer. A performance obligation must be identified and separated.

The purchase of vacuum cleaner contract gives raise to only one implied performance obligation. The warranty given is not a performance obligation but a quality assurance. And the warranty cost does not satisfy the contractual obligation of sale.

The one-year warranty is given only on the purchase of the vacuum cleaner. This warranty cannot be sold separately.

Therefore. V should recognize this cost as a warranty expense in the period of sale.

The extended warranty for a period of three years is sold separately. This is a separate performance obligation since the warranty for quality assurance is extended beyond the original period of one year.

This warranty can be purchased by customers separately which is priced separately from the product. This extended period warranty is not included in the implied contract.

Therefore, there exists only one performance obligation in the contract.

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Points A and B are graphed points on the coordinate plane below. Which ordered pair is the coordinate location which is halfway
Setler [38]

Answer:

I cant see the image it doesnt seem to be loading but here is how to do the problem-->.

Add both the x coordinates and divide by 2 (this is the new x coordinate for the midpt)

next:

Add both y coordinates and divide by 2(this is the new y coordinate for the midpt)

Step-by-step explanation:

5 0
3 years ago
7. how many tiles measuring
Margaret [11]

Answer:

245 tiles

Step-by-step explanation:

1 meter = 100 cm

Area of bathroom = 3.5m x 2.8m = 350x280 = 9800 cm²

Area of each tile = 20cm x 20cm = 400 cm²

Total number of tiles required = 9800/400 = 245

<u>Note</u>

Strictly speaking we have to find out how many tiles can be fitted in the length and breadth of the bathroom. Since the bathroom is 350 cm wide, we can fit 350/20cm = 17.5 tiles. However, there is no concept of 1/2 tile so the question has an ambiguity. along the width, we can fit 280/10 = 14 tiles

17.5 x 14 = 245 but if the question is reworded to how many tiles do we need to purchase to floor the bathroom it would be 18 x 14 = 252

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2 years ago
5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

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