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Solve the initial value problem:
dy——— = 2xy², y = 2, when x = – 1. dxSeparate the variables in the equation above:
Integrate both sides:
Take the reciprocal of both sides, and then you have
In order to find the value of
C₁ , just plug in the equation above those known values for
x and
y, then solve it for
C₁:
y = 2, when
x = – 1. So,
Substitute that for
C₁ into (i), and you have
So
y(– 2) is
I hope this helps. =)
Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>
1. a+3a+4b=5b
2. a+3a=5b-4b
3. 4a=5b-4b
4. 4a=b
a=1/4b
(I think 1/4b is the answer) hope this helps :)
The answer to the question
Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.
So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.
What do you mean... $245???