Answer:
$70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.
Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.
Step-by-step explanation:
Answer:
<u>Final Answer: Statements 1, 2 and 4 are correct.</u>
Step-by-step explanation:
Finding value of y:
2y + 3 = 15 => 2y = 12 => y = 6;
Finding value of x:
6x + 5 = 77 => 6x = 72 => x = 12;
Statement Number 1:
y² > 2x ? => 6² > 2 * 12 ? => 36 > 24 ?
Yes, 36 is bigger than 24, therefore statement one is correct.
Statement 2:
x = 2y ? => 12 = 2 * 6? => 12 = 12?
Yes, 12 is equal to 12. Statement 2 is correct.
Statement 3:
x + 2 = y + 10 ? => 12 + 2 = 6 + 10? => 14 = 16?
No, 14 is not equal to 16. Statement 3 is incorrect.
Statement 4:
y + 4 > x - 4 ? => 6 + 4 > 12 - 4 ? => 10 > 8 ?
Yes, 10 is bigger than 8. Statement 4 is correct.
<em>If this helped you please rate </em>
<u>Final Answer: Statements 1, 2 and 4 are correct.</u>
<u />
<u />
Answer:
19
Step-by-step explanation:
First, find the unit rate. (How much she makes in 1 hour.)
28.50/3 is 9.5
Now it asks for how much she will make in 2 hours.
9.5 x 2 is
19.
Answer:
No real solution- Not any of the options anyway
Step-by-step explanation:
So I replaced the x's with the two possible equations and then tried to solve...
2=4+(4x2-4)1/2
2=4+(8-4)1/2
2=4+(4)1/2
2=8(1/2)
2=4 Which is not true
10=4+(4x10-4)1/2
10=4+(40-4)1/2
10=4+36(1/2)
10=40(1/2)
10=20 Which is also not true
Therefore, there is no real solution
Answer:

Step-by-step explanation:
In every rhombus, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, plus, it measures 90° all around, so with that being said, you have your answer.
I am joyous to assist you anytime.